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class Shy : public Diffident { public: // ok: under Standard C++, the using declaration // creates an overloaded set of // base and derived class members void mumble( string whatYaSay ); using Diffident::mumble; // };

10 00 11 01

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In effect, the using declaration enters each named member of the base class into the scope of the derived class The base class member is now entered into the set of overloaded instances associated with the name of the member function within the derived class (The using declaration for a member function cannot specify the parameter list, only the member function name This means that if the function is overloaded within the base class, all the overloaded instances are added to the scope of the derived class type We cannot add only one instance of the set of overloaded base class members) Another common misunderstanding of new C++ programmers is the extent to which they may access the protected members of a base class When we write

class Query { public: const vector<location>* locations() const { return &_loc; } // protected: vector<location> _loc; //

file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm (818 / 1065) [2001-3-29 11:32:13]

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M1 and M2 while node C receives the messages M 3 and M 4 . Both nodes B and C apply a linear combination over the received messages and produce two encoded messages each. Node B produces messages K1 and K2 , and node C produces messages L1 and L2 . Finally, nodes B and C send out the encoded messages to the destination node D. Assume that the original messages M 1 , M 2 , M 3 , and M 4 can be represented as four-element vectors with the following expressions: 1 1 M1 = , 2 0 2 1 M2 = , 4 2 3 1 M3 = , 1 3 1 0 M4 = 1 0

we are saying that a class derived from Query may directly access the _loc data member, while the rest of the program must use the public access function What this means, however, is that the derived class has access to the protected _loc data member of its base class subobject The derived class does not have access to the protected members of an independent base class object For example:

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bool NameQuery:: compare( const Query *pquery ) { // ok: protected member of its Query subobject int myMatches = _locsize(); // error: has no direct access rights to the // protected member of an independent Query object int itsMatches = pquery->_locsize(); return myMatches == itsMatches; }

NameQuery has access to the protected members of only one Query class object: its own Query subobject (These protected members are accessed within the derived class through the implicit this pointer [the this pointer is introduced in Section 134]) The immediate solution to the compile-time error is to rewrite the compare() function to make use of the public location() member function:

bool NameQuery:: compare( const Query *pquery ) { // ok: protected member of its Query subobject int myMatches = _locsize(); // ok: use public access method int itsMatches = pquery->locations()->size(); return myMatches == itsMatches; }

Select, at will, the coef cients of the possible linear combinations that are applied at nodes B and C and work out possible values for the vectors L1 , L2 , K1 , and K2 . Show the form of the encoding vectors that are sent together with the information vectors and nally show the algebraic steps of the decoding process applied at node D, and demonstrate that the decoding process produces back the original messages M 1 , M 2 , M 3 , and M 4 . For simplicity, work out additions and products in the eld (R,+, ). 5. Consider the graph of Figure 4.16. Similarly to the case of exercise 4, node A generates four messages: M 1 , M 2 , M 3 , and M 4 . Node B receives the messages M 1 and M 2 , while node C receives the messages M 3 and M 4 . Both node B and node C apply a linear combination over the received messages and produce two encoded messages each. Node B produces the messages K1 and K2 , and node C produces

The real problem, however, is an incorrect design on our part Because _loc is a member of the Query base class, compare() properly belongs as a member of the Query class, not to the derived NameQuery class Often, member access problems between a derived and base class can be resolved by moving the operation to the class that contains the inaccessible member, as in this case This form of member access constraint does not apply within a class for other objects of its own class For example:

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