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If we were to assign ri a new value, we would not change dval but would instead change temp To the user, it is as if the change simply did not work (and it doesn't for all the good it does the user) const references don't exhibit this problem because they are read-only Disallowing non-const references to objects or values requiring temporaries in general seems a better solution than to allow the reference to be defined but seem not to work Here is an example that is difficult to declare correctly the first time We wish to initialize a reference to the address of a const object A non-const reference definition is illegal and is flagged as a compile-time error:

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const int ival = 1024; // error: requires a const reference int *&pi_ref = &ival;

Our first attempt to correct the definition of pi_ref might be the following, but it does not work do you see why

Due to node mobility, route failures which are determined by missing acknowledgments may occur frequently If a route failure occurs, an existing alternate path is used; otherwise, the source initiates the route discovery phase The expected overhead of ARA is very low since the route maintenance is carried out by the data packets Routing On-Demand Acyclic Multipath (ROAM) [13] The ROAM algorithm uses coordination among nodes along directed acyclic subgraphs that are de ned only.

z 1:0000 10 : Comment 16.2 The difference of two positive numbers could produce an under ow, as the nal value of e could be smaller than emin. 16.2.3 Addition and Subtraction

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const int ival = 1024; // still an error const int *&pi_ref = &ival;

If we read this definition from right to left, we discover that pi_ref is a reference to a pointer to an object of type int defined to be const Our reference isn't to a constant but rather to a nonconstant pointer that addresses a constant object The correct definition is as follows:

const int ival = 1024; // ok: this is accepted const int *const &pi_ref = &ival;

file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm (107 / 1065) [2001-3-29 11:32:03]

Figure 5.5. Forward ant route discovery phase. A forward ant (F) is sent from the sender (S) toward the destination node (D). The forward ant is relayed by other nodes, which initialize their routing table and the pheromone values [12].

Two primary differences between a reference and pointer are that a reference must always refer to an object and that the assignment of one reference with another changes the object being referenced and not the reference itself Let's look at an example When we write

int *pi = 0;

const int &ri = 0;

internally, recall that the following transformation takes place:

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Figure 5.6. Backward ant route discovery phase. The backward ant (B) has the same task as the forward ant. It is sent by the destination node toward the source node [12].

int temp = 0; const int &ri = temp;

Given two oating-point numbers (21)sign1.s1.Be1 and (21)sign2.s2.Be2, and a control variable operation, an algorithm is de ned for computing z ( 1)sign :s:Be ( 1)sign1 :s1 :Be1 ( 1)sign2 :s2 :Be2 , if operation 0, z ( 1)sign :s:Be ( 1)sign1 :s1 :Be1 ( 1)sign2 :s2 :Be2 , if operation 1:

The assignment of one reference with another is a second difference When, given the following,

int ival = 1024, ival2 = 2048; int *pi = &ival, *pi2 = &ival2;

pi = pi2;

on the routers distances to the respective destinations It is an extension of the DUAL [14] routing algorithm The main motivation comes from the fact that conventional on-demand schemes tend to use ooding during route discovery repeatedly until a destination is obtained If no route is found out initially, the source does not know whether to initiate another route discovery This may be a problem when a malicious router inde nitely queries the network for a nonexistence route causing network congestion Standard protocols have no mechanisms to protect against such type of attacks In ROAM, either a search query results in the destination path or all the routers determine that the destination is unreachable Each router in ROAM maintains distance, routing, and link cost tables.

ival, the object addressed by pi, remains unchanged pi, rather, is assigned the object that pi2 addresses ival2 in this case What is significant is that pi and pi2 now both address the same object (This can be a significant source of program error if we copy one class object with another in which one or more class members are pointers We'll look at this problem in detail in 14) When, however, given the following

int &ri = ival, &ri2 = ival2;

ri = ri2;

file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm (108 / 1065) [2001-3-29 11:32:03]

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